I have 2 questions, thanks in advance for any help anyone can give me.
I'm in the process of designing a project using a EM-408, and I was wondering if anyone could tell me if I disable the 408 using the enable pin, will it be able to re-acquire it's position faster than if I had simply cut the power?
I was also wondering what the current draw of these devices when disabled (i.e. enable pin low)? I'm thinking of connecting a 1F capacitor across the supply rails so that when the power to the device is cut it becomes disabled via the enable pin, and hopefully draws so little current the 1F can keep the device on standby (rather than off) for a long time.